tag:blogger.com,1999:blog-88396514368864195022012-02-16T09:03:22.034ZGénios da Matemática - 6º GGénios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.comBlogger251100tag:blogger.com,1999:blog-8839651436886419502.post-73140606040232298742008-04-17T14:56:00.003+01:002008-12-13T03:01:46.244Z7º Desafio<div style="text-align: justify;"><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://3.bp.blogspot.com/_ofegFh1miMo/SA-uryryflI/AAAAAAAAACw/7Vj1y7B5js8/s1600-h/mapa2.bmp"><span style=";font-family:";font-size:12;" ><span style="font-size:130%;">O João e os pais foram do Porto a Paços de Ferreira para comprarem uma estante para o seu quarto. Quis saber aproximadamente o número de quilómetros que iria percorrer e para isso utilizou o mapa que havia lá em casa e o que tinha aprendido sobre escalas nas aulas de Matemática.</span></span><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer; width: 313px; height: 256px;" src="http://3.bp.blogspot.com/_ofegFh1miMo/SA-uryryflI/AAAAAAAAACw/7Vj1y7B5js8/s400/mapa2.bmp" alt="" id="BLOGGER_PHOTO_ID_5192560962744516178" border="0" /></a><br /></div><div style="text-align: justify;"> <p class="MsoNormal" style="text-align: justify; font-style: italic;">Pegou numa régua, mediu<u> em linha <span style=""></span>recta a distância do Porto a Paços de Ferreira</u> <u>(<st1:metricconverter style="font-weight: bold;" productid="4,7 cm" st="on">4,7 cm</st1:metricconverter>).</u></p><p class="MsoNormal" style="text-align: justify;"> </p> <p class="MsoNormal" style="margin-left: 0.25in; text-align: left;"><!--[if !supportLists]--><span style="font-family: Wingdings;"></span><span style="font-weight: bold;font-size:130%;" ><span style="color: rgb(51, 51, 255);">Consulte a escala do mapa, e calcule o número de quilómetros que ele irá percorrer.</span></span></p> <br /><span style=";font-family:";font-size:12;" ><br /><br /></span></div><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-7314060604023229874?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-88233505563894811652008-04-17T14:52:00.002+01:002008-04-17T14:55:25.888+01:00Vencedores do 6º DesafioAs vencedoras do 6º desafio foram a Margarida e a Mariana.<br /><br />Parabéns meninas!!!!!!!!!!<div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-8823350556389481165?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-26484656545316821302008-04-17T14:51:00.000+01:002008-04-17T14:52:24.459+01:00Resposta ao 6º Desafio1- O Ernesto arrumou 30% dos chocolates.<br /><br />2- A Bia arrumou 1/4 dos chocolates.<br /><br />1/1-(3/10+1/4+1/5)= 1-(6/20+5/20+4/20)=1-(11/20+4/20)=<br />1-15/20=20/20-15/20=5/20=1/4<div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-2648465654531682130?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-44607105327553205052008-04-11T11:15:00.001+01:002008-12-13T03:01:46.642Z6º Desafio<div style="text-align: left;"><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_ofegFh1miMo/R_87G_KkCFI/AAAAAAAAACg/NxKjkPHfnkE/s1600-h/Percent.bmp"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer;" src="http://1.bp.blogspot.com/_ofegFh1miMo/R_87G_KkCFI/AAAAAAAAACg/NxKjkPHfnkE/s400/Percent.bmp" alt="" id="BLOGGER_PHOTO_ID_5187930286975092818" border="0" /></a><br /></div><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-4460710532755320505?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com1tag:blogger.com,1999:blog-8839651436886419502.post-43860081807132181892008-03-06T15:50:00.001Z2008-03-06T15:51:27.520ZVencedor do 4º desafioO vencedor deste desafio foi o Rui.<br /><br />Parabéns ao Rui!!!!!<div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-4386008180713218189?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-15510392134542567062008-03-06T15:35:00.002Z2008-04-04T11:51:35.900+01:00Resposta ao 5º desafio<div>1- A joaninha percorrerá uma distância de 3,8 cm.</div><br /><div> </div><br /><div> </div><br /><div>Ou seja: 0,6 x 3,14 = 1,884 3,8 cm<br /></div><br /><div> = 1,884 x 2= 3,768 <u><span style="font-size: 12pt; font-family: Arial;">~</span></u> 3,8 cm </div><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-1551039213454256706?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-83028086248694464482008-02-28T15:54:00.003Z2008-12-13T03:01:47.045Z5º Desafio<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://2.bp.blogspot.com/_ofegFh1miMo/R8bZsPBltJI/AAAAAAAAACY/9u2Xck4h3qY/s1600-h/Exercicio+8+de+2006.bmp"><img id="BLOGGER_PHOTO_ID_5172060576052262034" style="DISPLAY: block; MARGIN: 0px auto 10px; CURSOR: pointer; TEXT-ALIGN: center" alt="" src="http://2.bp.blogspot.com/_ofegFh1miMo/R8bZsPBltJI/AAAAAAAAACY/9u2Xck4h3qY/s400/Exercicio+8+de+2006.bmp" border="0" /></a><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-8302808624869446448?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-57018403975814703422008-02-28T15:44:00.004Z2008-03-06T15:31:27.705ZResposta ao 4º Desafio1- O artigo sobre o Elefante Africano ocupa 1/2 da página 5.<br /><br />2- Se a 4 e a 5 são as páginas do meio, existem 3 páginas antes da 4 e 3 depois da 5. Logo 3+3= 6. Mais as 2 páginas do meio, dá 8.<br /><br />Ou seja: 3+3+2=8<div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-5701840397581470342?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com1tag:blogger.com,1999:blog-8839651436886419502.post-82363258963851505742008-02-28T15:33:00.002Z2008-12-13T03:01:47.215Z4º Desafio<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_ofegFh1miMo/R8bVz_BltII/AAAAAAAAACQ/Ud0XNZrzVSA/s1600-h/Exercicio+8+de+2005.bmp"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer;" src="http://1.bp.blogspot.com/_ofegFh1miMo/R8bVz_BltII/AAAAAAAAACQ/Ud0XNZrzVSA/s400/Exercicio+8+de+2005.bmp" alt="" id="BLOGGER_PHOTO_ID_5172056311149737090" border="0" /></a><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-8236325896385150574?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com2tag:blogger.com,1999:blog-8839651436886419502.post-47598586943779939572008-02-28T15:27:00.002Z2008-02-28T15:32:00.004ZResposta ao 3º Desafio1- Falso<br />2- Verdadeiro<br />3- Verdadeiro<br />4- Verdadeiro<br /><br /><br />A Vencedora da Semana foi a Sara!<br /><span style="font-weight:bold;"><br />Parabéns à Sara!!</span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-4759858694377993957?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-89057765840758300742008-02-21T15:43:00.002Z2008-02-21T15:46:50.772Z3º Desafio<p class="MsoNormal" style="text-align: center;" align="center"><b style=""><i><span style="color: rgb(38, 38, 38);">Diga se é verdadeiro ou falso</span></i></b><i><span style="color: rgb(38, 38, 38);">:<o:p></o:p></span></i></p> <p class="MsoNormal" style=""><b><span style="color: black;">1. </span></b><i><span style="color: rgb(38, 38, 38);">Todo o paralelogramo cujas diagonais são iguais é um quadrado.<o:p></o:p></span></i></p> <p class="MsoNormal" style=""><i><span style="color: rgb(38, 38, 38);"><span style=""> </span></span></i><b><span style="color: rgb(0, 56, 241);">R.: <o:p></o:p></span></b></p> <p class="MsoNormal" style=""><b><span style="color: rgb(0, 56, 241);"><o:p> </o:p></span><span style="color: black;">2. </span></b><i><span style="color: rgb(38, 38, 38);">Todo o paralelogramo cujas diagonais são perpendiculares é um losango.<o:p></o:p></span></i></p> <p class="MsoNormal" style=""><b><span style="color: rgb(0, 56, 241);"><span style=""> </span>R.: <o:p></o:p></span></b></p> <p class="MsoNormal"><b><span style="color: black;">3. </span></b><i><span style="color: rgb(38, 38, 38);">Todo o quadrado é um rectângulo.<span style=""> </span><o:p></o:p></span></i></p> <i><span style="font-size: 12pt; font-family: "Times New Roman"; color: rgb(38, 38, 38);"><span style=""> </span></span></i><b><span style="font-size: 12pt; font-family: "Times New Roman"; color: rgb(0, 56, 241);">R.:<br /><br /></span></b> <p class="MsoNormal" style=""><b><span style="color: black;">4. </span></b><i><span style="color: rgb(38, 38, 38);">Todo o paralelogramo cujas diagonais são iguais e perpendiculares<o:p></o:p></span></i></p> <p class="MsoNormal" style=""><i><span style="color: rgb(38, 38, 38);">é um quadrado.<span style=""> </span></span></i><b><span style="color: rgb(0, 56, 241);"><br /></span></b></p><p class="MsoNormal" style=""><b><span style="color: rgb(0, 56, 241);">R.: <o:p></o:p></span></b></p> <br /><b style="font-style: italic;"><span style="font-size: 12pt; font-family: "Times New Roman"; color: rgb(0, 56, 241);"> </span></b><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-8905776584075830074?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com3tag:blogger.com,1999:blog-8839651436886419502.post-13648446137817871322008-02-21T15:29:00.002Z2008-02-21T15:34:46.584ZResposta ao 2º Desafio60: (5x1/4) = 60 : 5/4 = 240/5 = 48<br /><br />O Pedro vai demorar 48 dias a juntar papel para poder salvar uma árvore.<div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-1364844613781787132?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com1tag:blogger.com,1999:blog-8839651436886419502.post-73059175531810742102008-01-31T15:41:00.000Z2008-12-13T03:01:47.497Z2º Desafio<div style="text-align: left;"><a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://4.bp.blogspot.com/_ofegFh1miMo/R6HvvAVQA9I/AAAAAAAAACI/SWde5kFMrBY/s1600-h/Experiencia+3.bmp"><img style="margin: 0px auto 10px; display: block; text-align: center; cursor: pointer; width: 437px; height: 368px;" src="http://4.bp.blogspot.com/_ofegFh1miMo/R6HvvAVQA9I/AAAAAAAAACI/SWde5kFMrBY/s400/Experiencia+3.bmp" alt="" id="BLOGGER_PHOTO_ID_5161670238765319122" border="0" /></a><br /></div><img src="file:///C:/DOCUME%7E1/GRAAAD%7E1/DEFINI%7E1/Temp/moz-screenshot-30.jpg" alt="" /><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-7305917553181074210?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-24279095415763759382008-01-31T15:27:00.000Z2008-01-31T15:29:15.333ZResposta ao 1º Desafioc = 4,5cm; l = 4cm; h = 12cm; então:<br /><br />V = C x l x h<br /> = 4,5 x 4 x 12<br /> = 18 x 12<br /> = 216 cm3<br /><br />216 cm3 é o volume de um pacote de leite.<br />Como são 10 pacotes então, a caixa tem que ter um menor volume de:<br /><br />10 x 216 cm3 = 2160 cm3.<div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-2427909541576375938?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com1tag:blogger.com,1999:blog-8839651436886419502.post-90914692404662121422008-01-26T03:48:00.000Z2008-12-13T03:01:47.872Z1º Desafio<a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_ofegFh1miMo/R5quiAVQA7I/AAAAAAAAAB4/KaFffVYlH3o/s1600-h/Pacote+de+leite.bmp"><img style="margin: 0pt 0pt 10px 10px; float: right; cursor: pointer; width: 199px; height: 129px;" src="http://1.bp.blogspot.com/_ofegFh1miMo/R5quiAVQA7I/AAAAAAAAAB4/KaFffVYlH3o/s320/Pacote+de+leite.bmp" alt="" id="BLOGGER_PHOTO_ID_5159628222334239666" border="0" /></a><br /><p style="text-align: justify;" class="MsoNormal"><span style=";font-family:Arial;font-size:130%;" >A D. Gabriela vai arrumar 10 pacotes de leite numa caixa em forma de paralelepípedo.</span></p> <div style="text-align: left;"><span style=";font-family:Arial;font-size:14;" ><span style="font-size:130%;"><br /><br />A figura mostra as dimensões dos pacotes.<br /><br /><br /></span></span></div> <p class="MsoNormal" style="margin-left: 0.25in; text-align: justify;"><span style=";font-family:Arial;font-size:130%;" ><o:p> </o:p></span></p> <p class="MsoNormal" style="text-align: justify;"><span style="font-weight: bold;font-family:Arial;font-size:130%;" >Qual é o menor volume, em cm</span><span style="font-weight: bold;font-size:130%;" ><sup><span style="font-family:Arial;">3</span></sup></span><span style=";font-family:Arial;font-size:14;" ><span style="font-weight: bold;font-size:100%;" ><span style="font-size:130%;">, que pode ter a caixa?</span></span><o:p></o:p></span></p><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-9091469240466212142?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com1tag:blogger.com,1999:blog-8839651436886419502.post-35081614696125555082008-01-17T15:52:00.000Z2008-01-26T03:47:52.504ZActualizaçãoes<div style="text-align: justify;">A partir de agora, às Quintas- feiras vamos actualizar o <span class="blsp-spelling-error" id="SPELLING_ERROR_0">blogue</span>. Iremos pôr novas informações sobre a turma e alguns desafios matemáticos sobre as matérias de 5º e 6º ano.<br /><br />Vamos passar a ter <span style="font-weight: bold;">um desafio semanal,</span> diremos a resposta e o nome do respectivo vencedor na semana seguinte.<br /><br />Se quiserem participar podem faze-lo, dando as <span style="font-weight: bold;">respostas através dos comentários</span>.<br /><br />Para a próxima semana já haverá um desafio semanal.<br /><br /></div><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-3508161469612555508?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-55445063383605790162008-01-17T15:46:00.000Z2008-01-17T15:48:48.672ZA nossa turma<p class="MsoNormal"><span style="font-family: "Comic Sans MS";">Hoje, vamos falar um pouco sobre a nossa turma.<o:p></o:p></span></p> <p class="MsoNormal"><span style="font-family: "Comic Sans MS";">A nossa turma tem 17 elementos, é uma turma muito pequena.<o:p></o:p></span></p> <p class="MsoNormal"><span style="font-family: "Comic Sans MS";">Somos uma turma divertida, curiosa, animada e acima de tudo muito unida!<o:p></o:p></span></p> <p class="MsoNormal"><span style="font-family: "Comic Sans MS";">Nas aulas de matemática, a nossa professora ajuda-nos muito, ensina-nos coisas que nunca ouvimos falar, no início tudo parece complicado, mas no fundo até é simples.<o:p></o:p></span></p> <p class="MsoNormal"><span style="font-family: "Comic Sans MS";">Como podem ver no fundo do blogue temos fotos da sala, vão ver! <o:p></o:p></span></p> <span style="font-size: 12pt; font-family: "Comic Sans MS";">Hoje, a nossa professora fez um teste surpresa com exercícios das provas de aferição de anos passados, correu bem!!!!</span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-5544506338360579016?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-91478017876769400362007-12-27T05:10:00.000Z2007-12-27T05:13:03.485ZSolidariedade<span class="q" id="q_117192f64b0b81c9_0"><span><div style="color: rgb(204, 0, 0);"><span style="font-size:130%;"><strong>Ajuda de berço... basta só 1 click para ajudar</strong></span></div> <div><span style="color: rgb(0, 153, 0);font-size:85%;" ><span style="font-family:verdana;"></span><span style="font-size:130%;"><i style="color: rgb(0, 102, 0);"><span style="font-family:verdana;"><strong style="font-weight: normal;"> </strong></span></i></span></span></div><div><span style="color: rgb(0, 153, 0);font-size:85%;" ><span style="font-size:130%;"><i style="color: rgb(0, 102, 0);"><span style="font-family:verdana;"><strong style="font-weight: normal;">Pode/deve ser dado um clique por dia</strong></span></i><b><i><span style="font-family:verdana;"><strong style="font-weight: normal;"> </strong></span></i></b></span></span></div> <div style="color: rgb(0, 153, 0);font-family:verdana;"><span style="font-size:85%;"><br /></span><br /><span style="font-size:85%;">A "Ajuda de berço" que acolhe crianças dos 0 aos 3 anos, necessita da nossa ajuda.· </span><br /><span style="font-size:85%;">É um site que vive da publicidade que faz e são as empresas que o patrocinam e que ajudam esta associação.</span></div></span></span> <div style="color: rgb(0, 153, 0);"> </div> <p style="text-align: center;" align="center"><span class="q" id="q_117192f64b0b81c9_0"><span><div style="color: rgb(0, 153, 0);font-family:verdana;"> <div style="text-align: left;"><span style="font-size:85%;">Só temos que mostrar que visitámos o site em questão.·</span><br /><span style="font-size:85%;">Demora menos de um segundo a ir ao site e clicar no botão<br /><br /></span></div> </div> <div style="color: rgb(0, 153, 0);"> </div> <div><span style="font-size:130%;"><b><span style="color: rgb(51, 204, 0);">"UM COLO PARA CADA CRIANÇA":</span><br /><br /></b></span> </div> <div><span style="font-size:130%;"><a href="http://www.arcidadania.org/" target="_blank" onclick="return top.js.OpenExtLink(window,event,this)">http://www.arcidadania.org/</a></span></div></span></span></p><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-9147801787676940036?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-29666986789098333282007-12-27T04:21:00.001Z2007-12-27T04:42:06.902ZBOAS FESTAS<p style="text-align: center;"><b><i><span style="color: rgb(145, 0, 0);font-family:Edwardian Script ITC;font-size:7;" ><span style="font-weight: bold; color: rgb(145, 0, 0); font-style: italic;font-size:36;" ><img style="width: 439px; height: 219px;" src="http://mail.google.com/mail/?attid=0.1&disp=emb&view=att&th=1170c2c1dd43bc38" align="bottom" border="0" /></span></span></i></b></p> <p style="text-align: center; font-family: lucida grande;" align="center"><span style="font-size:180%;"><span style="color: rgb(255, 0, 0);"><b><i><span style="font-weight: bold; color: rgb(145, 0, 0); font-style: italic;">U</span></i></b><b><i><span style="font-weight: bold; color: rgb(145, 0, 0); font-style: italic;">m Fel</span></i></b><b><i><span style="font-weight: bold; color: rgb(145, 0, 0); font-style: italic;">iz Natal e um excelente </span></i></b><b><i><span style="font-weight: bold; color: rgb(145, 0, 0); font-style: italic;"><script><!-- D(["mb","Ano \n 2008 . \u003c/span\>\u003c/font\>\u003c/i\>\u003c/b\>\u003c/font\>\u003c/font\>\u003c/p\>\n \u003cp style\u003d\"text-align:center\" align\u003d\"center\"\>\u003cfont size\u003d\"6\"\>\u003cb\>\u003ci\>\u003cfont face\u003d\"Edwardian Script ITC\" color\u003d\"#ff0000\"\>\u003cspan style\u003d\"font-weight:bold;font-size:36pt;color:#910000;font-style:italic\"\>É \n o desejo desta amiga . \u003c/span\>\u003c/font\>\u003c/i\>\u003c/b\>\u003c/font\>\u003c/p\>\n \u003cp style\u003d\"text-align:center\" align\u003d\"center\"\>\u003cfont size\u003d\"6\"\>\u003cb\>\u003ci\>\u003cfont face\u003d\"Edwardian Script ITC\" color\u003d\"#ff0000\"\>\u003cspan style\u003d\"font-weight:bold;font-size:36pt;color:#910000;font-style:italic\"\>Manuela \n Marques\u003c/span\>\u003c/font\>\u003c/i\>\u003c/b\>\u003c/font\>\u003c/p\>\n \u003cp style\u003d\"text-align:center\" align\u003d\"center\"\>\u003cfont size\u003d\"6\"\>\u003cb\>\u003ci\>\u003cfont face\u003d\"Edwardian Script ITC\" color\u003d\"#ff0000\"\>\u003cspan style\u003d\"font-weight:bold;font-size:36pt;color:#910000;font-style:italic\"\>\u003c/span\>\u003c/font\>\u003c/i\>\u003c/b\>\u003c/font\> \u003c/p\>\n \u003cp style\u003d\"text-align:center\" align\u003d\"center\"\>\u003cfont size\u003d\"6\"\>\u003cb\>\u003ci\>\u003cfont face\u003d\"Edwardian Script ITC\" color\u003d\"#ff0000\"\>\u003cspan style\u003d\"font-weight:bold;font-size:36pt;color:#910000;font-style:italic\"\>\u003c/span\>\u003c/font\>\u003c/i\>\u003c/b\>\u003c/font\>\u003cfont size\u003d\"6\"\>\u003cb\>\u003ci\>\u003cfont face\u003d\"Edwardian Script ITC\" color\u003d\"#910000\"\>\u003cspan style\u003d\"font-weight:bold;font-size:36pt;color:#910000;font-style:italic\"\>`\u003c/span\>\u003c/font\>\u003c/i\>\u003c/b\>\u003c/font\>\u003cfont face\u003d\"Edwardian Script ITC\" color\u003d\"#910000\" size\u003d\"7\"\>\u003cspan style\u003d\"font-size:36pt;color:#910000\"\>\u003cimg height\u003d\"50\" src\u003d\"/mail/?attid\u003d0.2&disp\u003demb&view\u003datt&th\u003d1170c2c1dd43bc38\" width\u003d\"480\" align\u003d\"baseline\" border\u003d\"0\"\>\u003c/span\>\u003c/font\>\u003cfont face\u003d\"Arial\" size\u003d\"3\"\>\u003cspan style\u003d\"font-size:12pt;font-family:Arial\"\> \u003c/span\>\u003c/font\>\u003c/p\>\u003c/td\>\u003c/tr\>\u003c/tbody\>\u003c/table\>\n \u003cp style\u003d\"text-align:center\" align\u003d\"center\"\>\u003c/p\>\u003c/td\>\u003c/tr\>\u003c/tbody\>\u003c/table\>\n \u003cp\>\u003cfont face\u003d\"Arial\" size\u003d\"2\"\>\u003cspan style\u003d\"font-size:10pt;font-family:Arial\"\>\u003c/span\>\u003c/font\> \u003c/p\>\u003c/div\>\u003c/blockquote\>\u003cbr\>\n\u003chr\>\n\n\u003cp\>\n\u003chr\>\n\n\u003cp\>\u003c/p\>No virus found in this incoming message.\u003cbr\>Checked by AVG Free Edition. \n\u003cbr\>Version: 7.5.516 / Virus Database: 269.16.0/1194 - Release Date: 23-12-2007 \n17:27\u003cbr\>\u003c/p\>\u003c/div\>\n",0] ); //--></script>Ano 2008 . </span></i></b></span></span></p> <p style="text-align: center; font-family: lucida grande;" align="center"><span style="font-size:180%;"><b><i><span style="color: rgb(255, 0, 0);"><span style="font-weight: bold; color: rgb(145, 0, 0); font-style: italic;">É o desejo da professora: </span></span></i></b></span></p> <p style="text-align: center;" align="center"><span style="font-size:6;"><b><i><span style="color: rgb(255, 0, 0);font-family:Edwardian Script ITC;" ><span style="font-weight: bold; color: rgb(145, 0, 0); font-style: italic;font-size:36;" ><span style="font-family: lucida grande;font-size:180%;" >Graça Felício</span><br /></span></span></i></b></span> </p> <div style="text-align: center;"><span style="font-size:6;"><b><i><span style="color: rgb(255, 0, 0);font-family:Edwardian Script ITC;" ><span style="font-weight: bold; color: rgb(145, 0, 0); font-style: italic;font-size:36;" ></span></span></i></b></span><span style="font-size:6;"><b><i><span style="color: rgb(145, 0, 0);font-family:Edwardian Script ITC;" ><span style="font-weight: bold; color: rgb(145, 0, 0); font-style: italic;font-size:36;" >`</span></span></i></b></span><span style="color: rgb(145, 0, 0);font-family:Edwardian Script ITC;font-size:7;" ><span style="color: rgb(145, 0, 0);font-size:36;" ><img style="width: 435px; height: 50px;" src="http://mail.google.com/mail/?attid=0.2&disp=emb&view=att&th=1170c2c1dd43bc38" align="bottom" border="0" /></span></span><span style=";font-family:Arial;font-size:100%;" ><span style=";font-family:Arial;font-size:12;" ></span></span><br /></div><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-2966698678909833328?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-68471705560858982902007-12-18T17:10:00.000Z2007-12-18T17:14:12.433ZSIMETRIA -Trabalho de Grupo: João e Emanuel<div style="width:425px;text-align:left" id="__ss_202325"><object style="margin:0px" width="425" height="355"><param name="movie" value="http://static.slideshare.net/swf/ssplayer2.swf?doc=simetria-rui-e-emanuel-1197561073960517-3"/><param name="allowFullScreen" value="true"/><param name="allowScriptAccess" value="always"/><embed src="http://static.slideshare.net/swf/ssplayer2.swf?doc=simetria-rui-e-emanuel-1197561073960517-3" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="425" height="355"></embed></object><div style="font-size:11px;font-family:tahoma,arial;height:26px;padding-top:2px;"><a href="http://www.slideshare.net/?src=embed"><img src="http://static.slideshare.net/swf/logo_embd.png" style="border:0px none;margin-bottom:-5px" alt="SlideShare"/></a> | <a href="http://www.slideshare.net/praticamatematica/simetria-rui-e-emanuel" title="View 'Simetria - Rui e Emanuel' on SlideShare">View</a> | <a href="http://www.slideshare.net/upload">Upload your own</a></div></div><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-6847170556085898290?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-18201404252321915092007-12-18T16:57:00.000Z2007-12-18T17:02:19.487ZSIMETRIA -Trabalho de Grupo:<div style="width:425px;text-align:left" id="__ss_206192"><object style="margin:0px" width="425" height="355"><param name="movie" value="http://static.slideshare.net/swf/ssplayer2.swf?doc=simetria-119794034223446-5"/><param name="allowFullScreen" value="true"/><param name="allowScriptAccess" value="always"/><embed src="http://static.slideshare.net/swf/ssplayer2.swf?doc=simetria-119794034223446-5" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="425" height="355"></embed></object><div style="font-size:11px;font-family:tahoma,arial;height:26px;padding-top:2px;"><a href="http://www.slideshare.net/?src=embed"><img src="http://static.slideshare.net/swf/logo_embd.png" style="border:0px none;margin-bottom:-5px" alt="SlideShare"/></a> | <a href="http://www.slideshare.net/praticamatematica/simetria-206192" title="View 'Simetria' on SlideShare">View</a> | <a href="http://www.slideshare.net/upload">Upload your own</a></div></div><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-1820140425232191509?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com1tag:blogger.com,1999:blog-8839651436886419502.post-12029869171758384762007-12-18T16:55:00.000Z2007-12-18T16:56:26.398Zggg[slideshare id=206192&doc=simetria-119794034223446-5&w=425]<div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-1202986917175838476?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-13551928376376490422007-12-13T16:14:00.000Z2007-12-13T16:24:21.615ZSimetria<div id="__ss_202325" style="WIDTH: 425px; TEXT-ALIGN: left"><p align="center"><a href="http://www.blogger.com/[slideshare%20id=202325&doc=simetria-rui-e-emanuel-1197561073960517-3&w=425]"><embed src="http://static.slideshare.net/swf/ssplayer2.swf?doc=" width="425" height="355" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true"></embed></a></p><div style="FONT-SIZE: 11px; PADDING-TOP: 2px; FONT-FAMILY: tahoma,arial; HEIGHT: 26px"><a href="http://www.slideshare.net/?src=embed"><img style="BORDER-RIGHT: 0px; BORDER-TOP: 0px; MARGIN-BOTTOM: -5px; BORDER-LEFT: 0px; BORDER-BOTTOM: 0px" alt="SlideShare" src="http://static.slideshare.net/swf/logo_embd.png" /></a> <a title="View 'Simetria - Rui e Emanuel' on SlideShare" href="http://www.slideshare.net/praticamatematica/simetria-rui-e-emanuel">View</a> <a href="http://www.slideshare.net/upload">Upload your own</a></div></div><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-1355192837637649042?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-48063288783278731392007-12-12T11:24:00.000Z2007-12-12T11:38:26.016ZSimetrias...<span style="font-family:verdana;font-size:130%;">Nas aulas 47 e 48, começamos a apresentar alguns trabalhos de grupo sobre a simetria.</span><br /><span style="font-family:verdana;"></span><br /><span style="font-family:verdana;"><span style="font-size:130%;">Hoje brilhou o grupo da Catarina Charrua, Mariana Costa, Margarida Melo e Diogo Almeida com a apresentação do seu trabalho:</span></span><div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-4806328878327873139?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0tag:blogger.com,1999:blog-8839651436886419502.post-44684096311501885942007-12-12T11:19:00.000Z2007-12-12T11:24:09.350ZGénios da MatemáticaBem vindos !!!<br /><br />Neste Blog, vamos publicar trabalhos que fizemos nas nossas aulas de Matemática...<div class="blogger-post-footer"><img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8839651436886419502-4468409631150188594?l=geniosdamatematica-6g.blogspot.com' alt='' /></div>Génios da Matemáticahttp://www.blogger.com/profile/08195246909448240783noreply@blogger.com0